2x/2x^2-5=(-x)

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Solution for 2x/2x^2-5=(-x) equation: 



2x/2x^2-5=(-x)

We move all terms to the left:

2x/2x^2-5-((-x))=0



Domain of the equation: 2x^2!=0

x^2!=0/2

x^2!=√0

x!=0

x∈R



We add all the numbers together, and all the variables

2x/2x^2-((-1x))-5=0

We multiply all the terms by the denominator


2x-(((-1x)))*2x^2-5*2x^2=0

Wy multiply elements

-10x^2+2x-(((-1x)))*2x^2=0

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